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Further Integration (videos, notes, quizzes with correction) - Welcome To Class

Further Integration (videos, notes, quizzes with correction): Introduction Topics

Introduction

• 1 - Welcome To Class

: 0:03:44 mins

• 2 - Presentation of Objectives

: 0:05:36 mins

• View PDF Notes Take Quiz

Lessons: Further Integration

• 1 - Presentation of Objectives

: 0:05:36 mins

• 2 - INTRODUCTION AND RECALLS OF BASIC INTEGRALS

: 0:19:41 mins

• 3 - 3-BASIC INTEGRALS (PART2)

: 0:07:38 mins

• 4 - BASIC INTEGRATION TECHNIQUES-INTEGRATION BY PARTS

: 0:18:58 mins

• 5 - BASIC INTEGRATION TECHNIQUES -SUBSTITUTION METHOD (PART 1)

: 0:07:15 mins

• 6 - BASIC INTEGRATION TECHNIQUES- SUBSTITUTION METHOD (PART2)

: 0:05:51 mins

• 7 - GCE TYPE QUESTIONS (JUNE 2020 QUESTION 3)

: 0:17:43 mins

• 8 - GCE TYPE QUESTIONS (JUNE 2018 QUESTION 4)

: 0:11:40 mins

• 9 - GCE TYPE QUESTIONS (JUNE 2018 QUESTION 4 part 2)

: 0:13:47 mins

• View PDF Notes Take Quiz

You must logged in to ask a question.
• Nov. 12, 2022, 7:59 p.m.

Please I have a problem on series and sequence

• Nov. 12, 2022, 7:59 p.m.

Please I have a problem on series and sequence

• May 26, 2022, 9:05 a.m.
Lynn

question 31 june 2020 has a problem, it is not showing

• May 27, 2022, 8:19 p.m.
Yuyen

Thanks for th update lynn, did you propose something with respect to it????

• April 24, 2022, 5:31 p.m.
Nkatow Elvis

Take note

• April 16, 2022, 12:54 a.m.
KENG ElSON

Kernel:

It is a vector that maps unto the zero vector under the transformation. It is otherwise called the nulls space of the transformation. Let's consider an example below.... Find the kernel of the transformation T whose matrix is  $M&space;=&space;\begin{bmatrix}&space;2&&space;1\\&space;-1&&space;4&space;\end{bmatrix}$

Solution

Let the kernel be the vector  $X=&space;\binom{x}{y}$. Then we have that

$MX&space;=&space;0_2$

$\Rightarrow&space;\begin{bmatrix}&space;2&1&space;\\&space;-1&&space;4&space;\end{bmatrix}\binom{x}{y}&space;=&space;\binom{0}{0}$

$\Rightarrow&space;\left\{\begin{matrix}&space;2x&space;+y&space;&=0&space;\\&space;-x&space;+4y&&space;=&space;0&space;\end{matrix}\right.$

$\Rightarrow&space;x&space;=&space;0,&space;y&space;=&space;0$

Hence  $X&space;=&space;ker(T)&space;=&space;\binom{0}{0}$

• April 16, 2022, 12:24 a.m.
Boum paul

Sir can you explain to me the concept of kernel and image in transformation

• April 16, 2022, 12:26 a.m.
KENG ElSON

Hello boul Paul. Be patient, your explanation is coming

• March 12, 2022, 2:55 p.m.
KENG ElSON

Good luck to everyonen Further Maths 1

• March 8, 2022, 4:37 a.m.
Zulay Jouonang

Please i face a lot of difficulties with moment of inertia urgennntttt!!!!!!

Instructors

• MECHANICAL ENGINEER

• Ecole Normale Supérieure des Travaux Publics

• public works Yaoundé

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