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June 2018 and 2019 Paper 2 GCE A/L Pure Mathematics with Mechanics - Introduction to GCE A/L 2019
June 2018 and 2019 Paper 2 GCE A/L Pure Mathematics with Mechanics: Introduction Topics
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1 - Introduction to GCE A/L 2019
: 0:01:53 mins
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2 - Question 1a GCE A/L 2019
: 0:06:37 mins
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3 - Introduction to GCE A/L 2018
: 0:01:11 mins
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4 - Question 1 GCE A/L 2018
: 0:07:42 mins
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Take Quiz
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1 - Introduction
: 0:01:53 mins
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2 - Question One i-a
: 0:06:37 mins
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3 - Question One ib
: 0:04:53 mins
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4 - Question Two
: 0:13:11 mins
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5 - Question Three i-a
: 0:04:49 mins
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6 - Question Three i-b
: 0:02:14 mins
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7 - Question Three ii
: 0:04:12 mins
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8 - Question Four i
: 0:06:27 mins
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9 - Question Four ii
: 0:03:41 mins
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10 - Question Five i
: 0:10:22 mins
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11 - Question Five ii
: 0:03:18 mins
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12 - Question Six i
: 0:08:15 mins
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13 - Question Six ii
: 0:12:06 mins
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14 - Question Seven a
: 0:06:20 mins
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15 - Question Seven b
: 0:02:00 mins
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16 - Question Seven c
: 0:04:53 mins
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17 - Question Eight i-a
: 0:03:04 mins
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18 - Question Eight i-b
: 0:02:47 mins
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19 - Question Eight ii
: 0:02:56 mins
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20 - Question Nine i-a
: 0:04:44 mins
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21 - Question Nine i-b
: 0:02:01 mins
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22 - Question Nine ii
: 0:03:26 mins
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23 - Question Ten i
: 0:06:28 mins
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24 - Question Ten ii
: 0:11:09 mins
View PDF Notes
Take Quiz
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1 - Introduction
: 0:01:11 mins
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2 - Question No. 1
: 0:07:42 mins
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3 - Question No. 2a
: 0:03:27 mins
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4 - Question No. 2b
: 0:11:53 mins
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5 - Question No. 3 i
: 0:05:09 mins
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6 - Question No. 3 ii
: 0:03:39 mins
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7 - Question No. 4 i
: 0:03:21 mins
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8 - Question No. 4 ii
: 0:03:18 mins
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9 - Question No. 5 i
: 0:02:23 mins
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10 - Question No. 5 ii
: 0:03:11 mins
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11 - Question No. 6
: 0:07:38 mins
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12 - Question No. 7 i
: 0:04:13 mins
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13 - Question No. 7 ii
: 0:03:25 mins
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14 - Question No. 8 i
: 0:02:40 mins
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15 - Question No. 8 ii
: 0:07:18 mins
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16 - Question No. 9 i
: 0:07:20 mins
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17 - Question No. 9 ii
: 0:07:24 mins
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18 - Question No. 10
: 0:12:52 mins
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Introduction
Pure Math Mech June 2019 Paper 2 Solutions
Pure Math Mech June 2018 Paper 2 Solutions
Comments
Instructors
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MECHANICAL ENGINEER
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Ecole Normale Supérieure des Travaux Publics
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None
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NATIONAL ADVANCED SCHOOL OF PUBLIC WORKS YAOUNDE
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Faculty of Engineering and Technology of the University of Buea
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Faculty of Engineering and Technology of the University of Buea
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Please help me solve this problem
Question 2 june 2018 from your calculations e=1/3
Page 3
Page 2
Solution to June 2018 qn 7 by Johan
This is thé solution to the question (# Q6 PMM GCE jeune 2018)
Question 7 June 2018
Using : P/v = 14.28×1000/6m/s
=2371.6N
a- considering the car and the carriage as a single body the acceleration of the system
F - R = ma
2371.6 - (639 - 280) = ( 1400 +700)a
2021.6 = 2100a
a= 0.96m/s^2
b- T - 280 = 700a
T - 280 = 490
T = 770N
c- F = P/V
= 14.28 × 1000/12
= 1190N
So, F - R = ma
1190-(630-230) = 1400+ 700a
280 = 2100a
a = 0.13 m/s^2
d- time taken ,
We have first,280=700a
a=-0.4m/s^2
Retardation of its carriage at rest
Using
V= u + at
0= 12 + ( -0.4)t
-12= -0.4t
T= 30 s
Faith's solution
That was good Faith but you made a mistake when calculating the acceleration in the (a) part of the question. You were supposed to add the resistances not subtract them. F-R=ma, R = 639 + 280 = 919, a = (F-R)/m = (2371.6-919)/(1400+700) = 0.7 in meters per squared seconds
This is the solution to the question on impacts (# GCE june 2018 Q7)
You've not uploaded any solution Rene, please do so this evening