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Polynomials (videos, notes and quizzes with corrections) - Class: Overview
Polynomials (videos, notes and quizzes with corrections) : Introduction Topics
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1 - Class: Overview
: 0:03:19 mins
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1 - Overview
: 0:03:19 mins
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2 - Addition and Subtraction of Polynomials
: 0:01:36 mins
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3 - Multiplication and Division of Polynomials
: 0:04:52 mins
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4 - Polynomial Theorem
: 0:05:19 mins
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5 - GCE Past Questions
: 0:06:42 mins
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Introduction
Polynomials
Please help me solve this problem
Question 2 june 2018 from your calculations e=1/3
Page 3
Page 2
Solution to June 2018 qn 7 by Johan
This is thé solution to the question (# Q6 PMM GCE jeune 2018)
Question 7 June 2018
Using : P/v = 14.28×1000/6m/s
=2371.6N
a- considering the car and the carriage as a single body the acceleration of the system
F - R = ma
2371.6 - (639 - 280) = ( 1400 +700)a
2021.6 = 2100a
a= 0.96m/s^2
b- T - 280 = 700a
T - 280 = 490
T = 770N
c- F = P/V
= 14.28 × 1000/12
= 1190N
So, F - R = ma
1190-(630-230) = 1400+ 700a
280 = 2100a
a = 0.13 m/s^2
d- time taken ,
We have first,280=700a
a=-0.4m/s^2
Retardation of its carriage at rest
Using
V= u + at
0= 12 + ( -0.4)t
-12= -0.4t
T= 30 s
Faith's solution
That was good Faith but you made a mistake when calculating the acceleration in the (a) part of the question. You were supposed to add the resistances not subtract them. F-R=ma, R = 639 + 280 = 919, a = (F-R)/m = (2371.6-919)/(1400+700) = 0.7 in meters per squared seconds
This is the solution to the question on impacts (# GCE june 2018 Q7)
You've not uploaded any solution Rene, please do so this evening