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June 2019 and 2018 Paper 3 GCE A/L Pure Mathematics with Mechanics - Introduction to GCE A/L 2019 Solution
June 2019 and 2018 Paper 3 GCE A/L Pure Mathematics with Mechanics: Introduction Topics
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1 - Introduction to GCE A/L 2019 Solution
: 0:01:15 mins
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2 - Question 1a GCE A/L 2019
: 0:03:56 mins
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3 - Introduction to GCE A/L 2018
: 0:01:05 mins
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4 - Question 1 GCE A/L 2018
: 0:02:25 mins
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1 - Introduction
: 0:01:15 mins
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2 - Question No. 1a
: 0:03:56 mins
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3 - Question No. 1b
: 0:03:31 mins
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4 - Question No. 1c
: 0:04:21 mins
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5 - Question No. 2a
: 0:07:56 mins
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6 - Question No. 2b
: 0:02:33 mins
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7 - Question No. 2c
: 0:01:27 mins
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8 - Question No. 3a
: 0:09:08 mins
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9 - Question No. 3b
: 0:02:23 mins
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10 - Question No. 3c
: 0:02:18 mins
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10 - Question No. 3d
: 0:02:03 mins
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11 - Question No. 3e
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12 - Question No. 4 i-a
: 0:04:32 mins
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13 - Question No. 4 i-b
: 0:06:51 mins
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14 - Question No. 4 ii
: 0:08:22 mins
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15 - Question No. 5a
: 0:07:09 mins
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16 - Question No. 5b
: 0:08:53 mins
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17 - Question No. 6a
: 0:04:11 mins
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18 - Question No. 6b
: 0:03:08 mins
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19 - Question No. 6c
: 0:08:33 mins
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20 - Question No. 7a
: 0:18:14 mins
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21 - Question No. 7b
: 0:11:03 mins
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2 - Question No. 1a
: 0:02:25 mins
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3 - Question No. 1b
: 0:02:43 mins
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4 - Question No. 1c
: 0:02:58 mins
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5 - Question No. 1d
: 0:05:53 mins
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6 - Question No. 2a
: 0:05:19 mins
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7 - Question No. 2b,c
: 0:06:17 mins
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8 - Question No. 3 i-a
: 0:05:52 mins
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9 - Question No. 3 i-b
: 0:07:58 mins
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10 - Question No. 3 ii
: 0:03:50 mins
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11 - Question No. 4
: 0:10:02 mins
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12 - Question No. 5a
: 0:09:36 mins
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13 - Question No. 5b
: 0:02:23 mins
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14 - Question No. 6a
: 0:07:11 mins
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15 - Question No. 6b
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16 - Question No. 7a
: 0:06:01 mins
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17 - Question No. 7 b,c
: 0:02:55 mins
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18 - Question No. 7d
: 0:03:14 mins
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19 - Question No. 8 i
: 0:03:28 mins
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20 - Question No. 8 ii
: 0:02:01 mins
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21 - Question No. 8 iii
: 0:07:13 mins
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Introduction
Pure Math Mech June 2019 Paper 3 Solutions
Pure Math Mech June 2018 Paper 3 Solutions
Please help me solve this problem
Question 2 june 2018 from your calculations e=1/3
Page 3
Page 2
Solution to June 2018 qn 7 by Johan
This is thé solution to the question (# Q6 PMM GCE jeune 2018)
Question 7 June 2018
Using : P/v = 14.28×1000/6m/s
=2371.6N
a- considering the car and the carriage as a single body the acceleration of the system
F - R = ma
2371.6 - (639 - 280) = ( 1400 +700)a
2021.6 = 2100a
a= 0.96m/s^2
b- T - 280 = 700a
T - 280 = 490
T = 770N
c- F = P/V
= 14.28 × 1000/12
= 1190N
So, F - R = ma
1190-(630-230) = 1400+ 700a
280 = 2100a
a = 0.13 m/s^2
d- time taken ,
We have first,280=700a
a=-0.4m/s^2
Retardation of its carriage at rest
Using
V= u + at
0= 12 + ( -0.4)t
-12= -0.4t
T= 30 s
Faith's solution
That was good Faith but you made a mistake when calculating the acceleration in the (a) part of the question. You were supposed to add the resistances not subtract them. F-R=ma, R = 639 + 280 = 919, a = (F-R)/m = (2371.6-919)/(1400+700) = 0.7 in meters per squared seconds
This is the solution to the question on impacts (# GCE june 2018 Q7)
You've not uploaded any solution Rene, please do so this evening